The statement will be m∠ABC = m∠GHI.
Reason: ∠ABC ≅ ∠GHI
Answer:
Step-by-step explanation:
4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.
b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.
c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.
d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.
e). If a parallelogram has four congruent sides, then it must be a SQUARE.
5). Given quadrilateral SELF is a rhombus.
a). All sides of a rhombus are equal,
Therefore, ES = EL = 25
b). Diagonals of a rhombus bisects the opposite angles,
Therefore, m∠ELS = m∠FLS
3x - 2 = 2x + 7
3x - 2x = 7 + 2
x = 9
c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.
m∠ELF = 2(m∠ELS) = 2(2y - 9)
m∠LES = 2(m∠LEF) = 2(3y + 9)
And 2(2y - 9) + 2(3y + 9) = 180
(2y - 9) + (3y + 9) = 90
5y = 90
y = 18
X+y=156
<span>0.05x+0.25y=21.6
-1/4*/ x+y=156
1/20x+1/4y=216/10
-1/4x-1/4y=156*-1/4=-39
</span>1/20x+1/4y=216/10
<span>+--------------------------
-4/20x=-17,4
x=87
</span>x+y=156
<span>
87+y=156 y=69
this question answer is </span><span>87 nickels and 69 quarters</span><span>
</span>
By the mid point formula is my best guess
Answer:
Step-by-step explanation:
area of base = π4² = 16π in²
lateral area = 2πrh = 2π·4·6 = 48π in²
surface area = 2×16π + 48π = 80π in² ≅ 251.3 in²
