The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Process:
1. 21+24n= 7
2. 24n= 7 - 21
3. 24n= -14
Answ: n= -7/12
For 6 plug in each of the answers for x and see if the product =3.2
Answer for 6: A
For 7 you turn the percentage into a decimal and multiply that by the number in which you know and you find the answer.
Answer for 7: D
<span>D: a line passing through the points (2, –6) and (4, –16)</span>
Here are the 4 inequality signs.
---> a is less than b
---> a is less than or equal to b
---> a is greater than b
---> a is greater than or equal to b
For the second and fourth lines above, the two sides may or may not be equal.
For the first and third lines above, the two sides cannot be equal.
