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3 years ago

7

Find the values of a, b, and c.

1 answer:

rodikova [14]3 years ago

4 0

Answer:

94°, 120°, 152°

Step-by-step explanation:

78°=(b+36°)/2 ⇒ b/2=78°-18° ⇒ b/2=60° ⇒ b=120°
87°=(120°+x)/2 ⇒ x/2=86°-60° ⇒ x= 52°
c=360°-(120°+52°+36°)= 152°
a=(152°+36°)/2=94°

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$x^3-12x^2-19x+20 = 0\\Let \ p(x) = x^3-12x^2-19x+20$

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±1, ±2 and ±3 are not the factors of given polynomial.

Putting x = 4 in the given polynomial

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So, x = 5 is not a factor of p(x)

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So, x = -5 is not a factor of p(x)

Putting x = 10 in the given equation

$p(10) = (10)^3+12(10)^2-19(10)+20\\p(10) = 1000+1200-190+20\\p(10) = 2030$

So, x = 10 is not a factor of p(x)

Putting x = -10 in the given equation

$p(-10) = (-10)^3+12(-10)^2-19(-10)+20\\p(-10) = -1000+1200+190+20\\p(-10) = 410$

So, x = -10 is not a factor of p(x)

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$p(20) = (20)^3+12(20)^2-19(20)+20\\p(20) = 8000+4800-380+20\\p(20) = 12440$

So, x = 20 is not a factor of p(x)

Putting x = -20 in the given equation

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So, x = -20 is not a factor of p(x)

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