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Blizzard [7]
3 years ago
9

Not shure how to do this someone help!!

Mathematics
1 answer:
Anika [276]3 years ago
7 0

-- the greatest common factor of the 15, the 9, and the 24 is 3 .

-- the greatest common factor of the b⁴, the b⁵, and the b³ is b³.

-- the greatest common factor of the c³, the c², and the c¹, is c¹.

-- the greatest common factor of the d², the d¹, and the d³ is d¹.

-- SO, the greatest common factor of the whole thing is  ( 3 b³ c d ) .

Can you factor that out of the big mess ?

Please try it.

You should get (3 b³cd) (5 bc²d - 3 b²c - 8 d²) .

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Answer:

171

Step-by-step explanation:

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Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

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