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cluponka [151]
3 years ago
7

A lawn sprinkler spins in a circle. The sprinkler covers a radius of 12 feet. Which choice is the closest to the area of lawn th

at the sprinkler can cover?
Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0

Answer:

Step-by-step explanation:

The formula for the area of a circle is π r^2.

3.14 (12x12) = 452.16

Approximately 450sqft

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For 1 the equation of the parabola is y = x^2 - 8x + 3
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7. The graph shows the height, h, in feet, of water
MariettaO [177]

The domain is talking about the "range" of the horizontal axis therefore you will be focusing on the x-intercepts.

The answer will be All non-negative real numbers less than or equal to 18

because the x-intercepts lies at 0 and 18. The answer makes sense because the furthest you can go is 18 ft and the closest you could go is 0 ft. The "all non-negative real numbers" puts a restriction on the least distance it could travel so that means that it stops at 0 ft because if you go any further, you will end up in the negatives and it clearly states "non-negative".

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Find the area of the circle. Round your answer to the nearest hundredth. 15in
jekas [21]
Answer is 47.25

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4 0
3 years ago
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
I need help with this please
zheka24 [161]
Number 2




Step by step:


:)
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