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Stella [2.4K]
3 years ago
5

If correct I’ll give brainlist

Mathematics
1 answer:
AnnyKZ [126]3 years ago
6 0

Answer:

C. is the only one that makes sense, but the real answer is (-15, 0)

(っ◔◡◔)っ ♥ Hope It Helps ♥

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How might we know whether x is a positive number, negative number, or zero, without solving the equation? 5x = -16.5​
pochemuha
To be able to get the negative number you have to divide x by a negative number to get your result. Seeing the solution is a negative number but your left side of the equation is a positive number tells us we have to divide by a negative number on the left side and right to give us the solution... (I think)
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3 years ago
3-3[6-(3-7)]+3(7-4) evaluate the expression
enot [183]

Answer:

-18

Step-by-step explanation:

3-3(6-(3-7))+3(7-4)\\\\=3-3(6-(-4))+3(7-4)\\\\=3-3(6+4)+3(7-4)\\\\=3-3(10)+3(7-4)\\\\=3-3(10)+3(3)\\\\=3-30+3(3)\\\\=3-30+9\\\\=-27+9\\\\=-18

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3 years ago
A car salesperson earns a 5.8% commission on every car sold. How much commission will the salesperson earn on the sale of a $28,
MrRa [10]

Answer:

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Step-by-step explanation:

You do .58 times 28,400. Then you move the decimal place over 1 place to the left. Because it is already 5.8%

5 0
3 years ago
Read 2 more answers
Given the points R (6,-2) and T (-9,- 7), find the coordinates of point S on line RT such that the ratio of RS to ST is 3 : 2​ p
Sholpan [36]

Answer:

(-3, -5)

Step-by-step explanation:

By using the distance formula, we see that the length of RT is \sqrt{(6+9)^2+(-2+7)^2} which equals 5\sqrt{10}.

The ratio of RS to ST is 3:2, so we can write the distance of RS as (5\sqrt{10} / 5) * 3 which equals 3\sqrt{10}. The distance of ST is then 2\sqrt{10}.

Since we know the distance of RS and ST, we can find the coordinates of point S by using the distance formula again:

\sqrt{(6-x)^2+(-2-y)^2} = 3\sqrt{10} and \sqrt{(-9-x)^2+(-7-y)^2} = 2\sqrt{10}

We solve for x and y, getting (-3, -5).

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3 years ago
How to divide 82 and 8688
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Answer:

105.9512195121

just use a calculator or do ~long division~

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4 years ago
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