Option 3:
m∠ABC = 66°
Solution:
Given 
and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines:
</u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem:
</u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.
Step-by-step explanation:
Since all 3 sides of the triangle is equal, it is not only an isosceles, but an equilateral triangle.
x = 8sin60° = 6.928 or sqrt48.
Answer:
Area of rectangle = l x b
18 = l x b
Factors of 18 =
1 x 18 = 18
2 x 9 = 18
3 x 6 = 18
So each of the sides can be either 1cm and 18 cm, 2cm and 9cm and 3cm and 6cm.
Answer:
70
Step-by-step explanation:
7^2 - ( 6-3^3)
PEMDAS
Parentheses first
7^2 - ( 6-3^3)
The exponent in the parentheses first
7^2 - ( 6-27)
7^2 - ( -21)
Now the exponent
49 - (-21)
Now subtract
49 +21
70
