Given:
The length of the rectangle = 16 ft
The width of the rectangle = 12 ft
The diameter of the semicircle = 12 ft
To find the area of the given figure.
Formula
where,
be the area of the given figure
be the area of the rectangle
be the area of the semicircle.
- The area of the rectangle =
where, l be the length and b be the width - Area of the semicircle =
, r be the radius of the semicircle.
Now,
The radius of the semicircle r = 6 ft
Putting, r=6, l=16 and b= 12 we get,
sq ft
or,
sq ft
sq ft
or,
sq ft
So,
sq ft
= 248.52 sq ft
Rounding off to the nearest tenth, we get;
A=248.5 sq ft.
Hence,
The area of the composite figure is 248.5 sq ft.
Answer:
y=7x+4
Step-by-step explanation:
slope- intercept form is y=mx+c
m=7
so y=7x+c
substitute (0,4) into y=7x+c
so 4=(7x0)+c
c=4
so y=7x+4
Answer:
Choice D
Step-by-step explanation:
38/4 =9.5
Therefore, this number is between 9 and 10
Note:
38/4 = 9 remainder 2
Hence, the quotient is 9 which is a whole number
Answer:
X=-3
Step-by-step explanation:
5x - 9
-2x + 12
(+) (-)
7x = -21
X= -3
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