Answer:
Check below, please
Step-by-step explanation:
Step-by-step explanation:
1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)
When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say

2. For which values of x is f '(x) positive?
Whenever we have

then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.

3. For which values of x is f '(x) negative?
On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So

4.What do these values mean?

5.(b) For which values of x is f ''(x) zero?
In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly
at x=-4 and x=4
Answer: $965
Step-by-step explanation:
The used car is priced at $2,695.
If you borrow the money for the car, your payments will be $122 a month for 30 months. This means that the total amount of money that you would have paid at the end of 30 months at a rate of $122 per month is the amount paid per month multiplied by the total number of months. It becomes
Total payment = 122×30 = $3660
This means that you ended up paying higher than you would have paid if you paid cash.
Amount that you would have saved = amount paid over 30 months - cost of the car
Amount that you would have saved
= 3660 - 2695 = $965
Answer:
See answers below
Step-by-step explanation:
From the given functions, the equivalent function for when x = 0 is -(x-1)²
h(x) = -(x-1)²
h(0) = -(0-1)²
h(0)= -(-1)²
h(0) = -1
when x = 2, the equivalent function is -1/2x - 1
h(x) = -1/2x - 1
h(2) = -1/2(2) - 1
h(2) = -1-1
h(2) = -2
when x = 5, the equivalent function is -1/2x - 1
h(x) = -1/2x - 1
h(5) = -1/2(5) - 1
h(5) = -5/2-1
h(5) = -7/2
Answer:
<h2>30% is enrolled out-of-district.</h2>
Step-by-step explanation:
According to the word problem, the number is increased by 50%.
To increase a number by a percent, multiply the number and the percent.
We can do this by changing both percents to decimals.
To change a percent to a decimal, divide it by 100.


The number is INCREASED by 50% so 0.5 would become 1.5.

<h2>0.3 = 30%.</h2>