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3 years ago

Jackson borrows $400 with an interest rate of 1.5%.How much interest will he pay after 4 years?

Mathematics

1 answer:

mafiozo [28]3 years ago

6 0

Answer:

24 interest after 4 years

Step-by-step explanation:

I just took 400 and multiplied it to 1.5%(.015) to get 6 and then multiplied that to 4 to get 24 and you could it if you want. Ask if you have a question.

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Please answer as soon as possible. Please make sure to explain your answer.

ruslelena [56]

Answer:

The slope is y=-x

Step-by-step explanation:

Rise over run. Pick 2 points, then count the distance that is rose(can be neg) then the distance that it went horizontally. Put into a fraction form.

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3 years ago

It’s on solving systems of equations... can anyone help me pls

dalvyx [7]

The answer for this is (2,3)

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3 years ago

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igomit [66]

Answer:

8 square units

Step-by-step explanation:

Area of a rectangle= lenght x width

locating the four points on a Cartesian plane

lenght = BC= AD = (0,4)->(4,4) = 4units

width = AB = CD = (0,2)-> (0,4) = 2units

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3 years ago

Let p be the statement "I do my chores," and let q be the statement "I get my allowance." Which statement uses p as the hypothes

andrew-mc [135]

Step-by-step explanation:

given that

p= "I do my chores"

q= "I get my allowance."

The statement that uses p as hypothesis is, if "I do my chores", which leads to the conclusion of "I get my allowance."

hence the test/ hypothesis is if "I do my chores", i get my allowance

5 0

3 years ago

In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!

g100num [7]

the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

Step-by-step explanation:

$x^{3}$ = $- 64$

$x^{3} +64$ = 0

We can write 64 as $4^{3}$

$x^{3}$ + $4^{3}$ = 0

using the identity ( $x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} )$ )

we get,

= $(x+4) (x^{2} -x*4+4^{2} )$

= $(x+4)(x^{2} -4x+16)$ ....................(1)

solving the quadratic equation ,

$x^{2} -4x+16$ =0

solutions of this quadratic equation can be obtained by

$x=-b +- \sqrt{b^{2}-4ac } /2a$

let use y for factors

$x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16} / 2*x^{2}$

$x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}$

$x=4+-\sqrt{16-64}/2$

$x=4+-4\sqrt{3i} /2$

<u /> $x=2+-2\sqrt{3i}$ ..................(2)

from the equation 1 we have,

$x-4=0$

which gives solution $x=4$

and from equation 2 we got $x=2+-2\sqrt{3i}$

so the real solutions for the equation $x^{3}=-64$ are -

$x=4,2+-2\sqrt{3i}$

3 0

2 years ago