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aliina [53]
3 years ago
6

Make the number 18 using six "1"s.

Mathematics
1 answer:
natka813 [3]3 years ago
4 0

Answer:

(11-1-1)(1+1)

Step-by-step explanation:

revised

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In a recent survey, 72 out of 100 consumers reported that they preferred plastic bags instead of paper bags for their groceries.
kupik [55]

Answer:

a) P=0.03

b) α=0.05

c) 0.72

d) 100

e) 0.72

Step-by-step explanation:

a) The P-value is the probability of the sample result. In this case the P-value is 0.03.

b) The level of significance is the threshold of probabilty for the null hypothesis to be reejcted or not. It is contrasted with the P-value to know if the effect is significant. In this case, the level of significance is 0.05.

NOTE: if it is a two-side test, the level of significance is 0.1 (two times 0.05).

c) The sample proportion is the one that results from the sample data. In this case, the sample proportion is 0.72.

p=72/100=0.72

d) The sample size is the amount of consumers reported. In this case is 100 customers.

e) The null value is 0.72 (equal to the sample proportion), because it is tested if there is no difference between the population proportion and the sample proportion.

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3 years ago
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Antonio wants to choose a career path in which he would earn a median income of at least $20,000. He wants on-the-job training i
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PLEASE HELP! I WILL FAIL WITHOUT THIS :(
stealth61 [152]

Answer:

<u>Part A</u>

  • Its Q3 ⇒ 9

<u>Part B</u>

  • Its data between Q1 and Q3 ⇒ between 5 and 9

<u>Part C</u>

  • Its data to the left from Q1 ⇒ 5
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3 years ago
Solve the following equation. Remember to check for extraneous solutions 7/(b+3) + 5/(b-3) = (10b-2)/(b²-9).
vlabodo [156]

Answer:

b= 2 is the solution for the given equation.

Step-by-step explanation:

Here, the given expression is:

\frac{7}{(b+3)}  + \frac{5}{(b-3)} = \frac{10b -2}{(b^{2} -9)}

Simplifying Left side, we get

\frac{7}{(b+3)}  + \frac{5}{(b-3)}

= \frac{7(b-3) + 5(b+3)}{(b+3)(b-3)}

Also, by ALGEBARIC IDENTITY:x^{2} -y^{2} = (x+y)(x-y)

So, (b+3)(b-3) = b^{2} -9

So, LHS becomes \frac{7(b-3) + 5(b+3)}{b^{2} -9}

Compare both Left side, Right side we get

\frac{7(b-3) + 5(b+3)}{b^{2} -9} =   \frac{10b -2}{(b^{2} -9)}

or, 7(b-3) + 5(b+3) = 10b -2

⇒ 7b - 21 + 5b + 15 = 10b -2

or, 12b - 10b = 6-2

or, 2b = 4 ⇒ b = 4/2 = 2

⇒ b= 2 is the solution for the given equation.

7 0
4 years ago
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