Answer:
2 7/20
Step-by-step explanation:
here u go boo
3/2 and 9/10. Look at the denominators. 2 times what number equals 10. That number would be 5. So if you multiply the first fractions denominator by 5 you get 10. Do the same to the top. you get a new fracrion which is 15/10. Add normally. 15/10 + 9/10 = 24/10. In lowest terms it is 2 2/5 (2 wholes and 2 out of 5)
Answer:
128
Step-by-step explanation:
Answer:
k > 7
Step-by-step explanation:
Given the inequality statement: 4k - (5 + 3k) > 2
Distribute -1 into (5 + 3k):
4k -5 - 3k > 2
Next, add like terms:
k - 5 > 2
Add 5 to both sides of the inequality:
k - 5 + 5 > 2 + 5
k > 7
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Answer:
P(X ≥ 1) = 0.50
Step-by-step explanation:
Given that:
The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.
Then; the probability of success = 7/34 = 0.20588
Using Binomial distribution to determine the probability; we have:

where;
x = 0,1,2,...n and 0 < β < 1
and x represents the number of successes.
However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:
P(X ≥ 1) = 1 - P(X< 1)
P(X ≥ 1) = 1 - P(X =0)
![P(X \ge 1) = 1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%20%7B%5E3C__0%7D%20%280.21%29%5E0%20%281-0.21%29%5E%7B3-0%7D%20%5Cbigg%5D)
![P(X \ge 1) = 1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%201%20%5Ctimes%201%20%280.79%29%5E%7B3%7D%20%5Cbigg%5D)
P(X ≥ 1) = 1 - 0.50
P(X ≥ 1) = 0.50