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3 years ago

Using the function g(x) = -2x + 5, what would the input need to be for an output of -5?

Mathematics

1 answer:

vivado [14]3 years ago

7 0

Answer:

it would be -5

Step-by-step explanation:

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In a function, an input can have more than one output. True Or False ??

Fudgin [204]

False. For every x in the function's domain, f(x) describes the one single output.

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3 years ago

Simplify (5^0+4^-0•5)^2

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Answer:

anything raised to the power of zero= 1

(1+1/4^½)²

(1 + 1/2)²

(3/2)²

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=2.25

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2 years ago

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3 years ago

Factor each polynomial. Look for a GCF first

weeeeeb [17]

Answer:

20. $x\left(x-6\right)\left(x+8\right)$

22. $2\left(x+1\right)\left(x+4\right)$

24. $5m\left(m-1\right)\left(m+7\right)$

Step-by-step explanation:

20. $x^3+2x^{2} -48x$

The GCF is x, so you group it out of the equation first.

$x(x^{2} +2x-48)$

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

$?+?=2\\?*?=-48$

The two numbers would be -6 and 8. You then differentiate the squares.

$x\left(x-6\right)\left(x+8\right)$

22. $2x^{2} +10x+8$

The GCF is 2, so you must group it out.

$2(x^{2} +5x+4)$

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

$?+?=5\\?*?=4$

The two numbers would be 1 and 4. Finally, differentiate the squares.

$2\left(x+1\right)\left(x+4\right)$

24. $5m^{3} +30m^2-35m$

The GCF is 5m, so you must group it out.

$5m(m^2+6m-7)$

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

$?+?=6\\?*?=-7$

The two numbers would be -1 and 7. Finally, differentiate the squares.

$5m\left(m-1\right)\left(m+7\right)$

7 0

2 years ago

Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the n

Temka [501]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= $\frac{3}{8}$ of x

Total number of newspapers delivered in first hour= $\frac{3}{8}$ x

Number of newspapers left= x- $\frac{3x}{8}$

Number of newspapers left= $\frac{8x-3x}{8}$

Number of newspapers left= $\frac{5x}{8}$

Number of newspapers delivered in second hour=4/5 of $\frac{5x}{8}$

Number of newspapers delivered in second hour= $\frac{x}{2}$

Fraction of newspapers delivered in second hour is= $\frac{1}{2}$

Hence, the correct answer is $\frac{1}{2}$

8 0

3 years ago