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Shalnov [3]
3 years ago
10

Write the equation of each circle given its center and a point P that it passes through

Mathematics
2 answers:
Sedbober [7]3 years ago
8 0

Answer:

(x-1)^2+(y+2)^2=25.

Step-by-step explanation:

If the center of the circle is (1,-2) and the circle passes through the point (4,2), then the radius of the circle is

r=\sqrt{(1-4)^2+(-2-2)^2}=\sqrt{9+16}=5.

The equation of the circle with center (x_0,y_0) and radius r is

(x-x_0)^2+(y-y_0)^2=r^2.

In your case, the equation is

(x-1)^2+(y+2)^2=25.

hodyreva [135]3 years ago
6 0

Answer:

(x-1)²+ (y+2)² = 25 is the equation of circle.

Step-by-step explanation:

We have given the center (1,-2) and a point P (4,2) from which the circle is passes.

So, the radius of the circle is :

r = \sqrt{(4-1)^{2}+(2-(-2))^{2}}=\sqrt{25}=5

The equation of circle is :

(x - x₁)² +(y - y₁)² = r²     where (x₁,y₁) is the center of circle.

Putting the value in above equation we get,

(x-1)²+(y-(-2))² = (5)²

(x-1)²+ (y+2)² = 25 is the equation of circle.

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ryzh [129]

Answer:

The solution to the equation is as follows;

x =  \frac{5}{19} ,\ and \ y= \frac{2}{19}

Step-by-step explanation:

Given;

5x - 3y = 1

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2:   10x  - 6y = 2

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--------------------------

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substitute the value of x in any of the equations above and solve for y;

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