"Product" signifies multiplication, and "half" means divide by two (or multiply by 1/2). So half the product of b and c is (bc)/2 or (1/2)(bc).
We can find this integer using a system of equations. The first thing we look at is the first sentence.
Let's call X The first integer,
Let's call Y the second integer.
So, X+Y=61 and X-Y= 1
Using Substituion on the second equation, we get
X=Y+1
(Now we plug in Y+1 into the second equation for X)
So,
(Y+1)+Y=61
2Y=60
Y=30
So, one of the integers is 30.
Now to find the second, we go back to
X=Y+1
X=30+1
X=31.
So, the integers are 31 and 30.
Hope this helps!
Answer:
Step-by-step explanation:
find the composition of g(x)=x−1 and h(x)=
hence we will get,
(g∘h)(x)=g(h(x))= g(x−1)= f(√x)= -1+√x = √x -1
Now to find f(g(h(x))),
f(x)=x4+6 and g(h(x))=√x -1
hence , putt g(h(x)) in f(x) ,
f(g(h(x)))=
+6 -
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