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3 years ago

I’d rather draw a map than give someone Verbal directions true or false

Mathematics

2 answers:

Vikentia [17]3 years ago

7 0

Answer:

FALSE

Step-by-step explanation:

Drawing map takes a while but verbal directions are quite simple and easy to understand

Hope it helps!

Nataliya [291]3 years ago

4 0

Answer:

True because there would be more understanding

Step-by-step explanation:

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Help Ill give 100 points!

nata0808 [166]

Answer:

0, 1, 1/2

Step-by-step explanation:

First you would have to make them have the same denominators.

The lowest one they share is 24.

What ever you do to the bottom you have to do to the bottom.

1/6, times each by 4.

1 * 4 = 4

6 * 4 = 24

4/24.

Now you have to do the same thnig for 5/8.

But times it by 3, since 8 times 3 is 24.

5 * 3 = 15

8 * 3 = 24

15/24

Now subtract.

15 - 4 = 11/24

the difference is close to one half.

4/24 = 1/6 is close to 0.

15/24 = 5/8 is close to 1.

4 0

3 years ago

Which numerical pattern is nonlinear?

kow [346]

Answer:

I think it's the first one

Step-by-step explanation:

8 0

3 years ago

Round the following numbers to 1 decimal place,

svetoff [14.1K]

A) 68.8

b) 5.9

c) 634.9

d) 90.0

4 0

3 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0

3 years ago

HELP PLEASE I NEED TO PLOT THIS POINT :)

Afina-wow [57]

The point would be at (-6,5) I believe. Sorry if this is incorrect.

4 0

3 years ago