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Softa [21]
3 years ago
7

There are nine empty seats in a theater, and six customers need to find places to sit. How many different ways can these six sea

t themselves?
Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer: 60480

Step-by-step explanation:

Given : The number of empty seats in a theater = 9

The number of customers need to find places to sit =6

Since order matters here, so we use permutations

The permutations of n things taking r at a time is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Then, the number of ways to arrange 6 seat in 9 seats :-

^9P_6=\dfrac{9!}{(9-6)!}=\dfrac{9\times8\times7\times6\times5\times4\times3!}{3!}\\\\=60480

Hence, the number of ways to arrange 6 seat in 9 seats = 60480

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Step-by-step explanation:

Given

Let

x \to months

y \to mice

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Required

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