Given:
AD is an angle bisector in triangle ABC.
.
To find:
The value of
.
Solution:
AD is an angle bisector in triangle ABC.



According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.
Using angle sum property in triangle CAD, we get





Therefore, the angle of angle ADC is
.
Answer:
d
Step-by-step explanation:
cosA^2 = 1 - sinA^2
subtitute 1/4 below
= 1 - (1/4)^2
= 1 - 1/16
after calculation
= - 0.9682
Answer:
The value of v is 6° and the value of w is 15°
Step-by-step explanation:
we know that
When parallel lines are cut by a transversal line, the same-side exterior angles are supplementary and each pair of alternate interior angles is equal in measure
so
5v=2w -----> equation A
10w+5v=180 ----> equation B
substitute equation A in equation B and solve for w
10w+(2w)=180
12w=180
w=15°
Find the value of v
5v=2w -----> v=2w/5
v=2(15)/5=6°
therefore
The value of v is 6° and the value of w is 15°
Answer:
(-2,-2)
Step-by-step explanation:
The domain is -2 -2 because that's all the x values that are possible on this graph