All categories

3 years ago

The formula to convert °C to °F is:

Mathematics

1 answer:

PolarNik [594]3 years ago

3 0

Answer:

80.6

Step-by-step explanation:

F = 9/5 C + 32

F = (9/5)*27 + 32 Substitute 27 into the equation

F = 243 / 5 + 32 Multiply 9 and 27 together

F = 48.6 + 32 Divide by 5

F = 80.6 Add on 32

A very quick way to do this is to double your centigrade temperature and and 30 which you should be able to do in your head.

2*27 = 54 Add 30

54 + 30 = 84

This quick way will tell you if you get near the right answer.

You might be interested in

I NEED HELP I WILL MARK IT BRAINLY

lana66690 [7]

Answer:

W=2/(P-2L)

Step-by-step explanation:

4 0

3 years ago

7 yd<br> 4 yd<br> 18 yd<br> 11 yd<br> 14 yd

Dima020 [189]

Answer:

????????????

Step-by-step explanation:

8 0

3 years ago

If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.

ira [324]

$2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\$

$x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \ \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\ \frac{x}{4} =1.5$

7 0

3 years ago

In ΔGHI, the measure of ∠I=90°, the measure of ∠H=52°, and HI = 63 feet. Find the length of IG to the nearest tenth of a foot.

AveGali [126]

Answer:

80.6

Step-by-step explanation:

5 0

3 years ago

The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....

leonid [27]

Answer:

Step-by-step explanation:

Let the solution to

2x^2 + x -1 =0

x^2+ (1/2)x -(1/2)

are a and b

Hence a + b = -(1/2) ( minus the coefficient of x )

ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

2x^2-19x + 44 =0

B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

x^2 +(3/2) x -9/2 = 0

2x^2 + 3x -9 =0.

4 0

3 years ago