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lilavasa [31]
3 years ago
6

Which trigonometric ratios are correct for triangle ABC? Check all that apply.

Mathematics
1 answer:
Alina [70]3 years ago
5 0
Assuming the - are bullet points and not negative signs:
sin = opposite/hypotenuse
cos = adjacent / hypotenuse
tan = opposite / adjacent. 
Also remember the special properties of the 30 - 60 - 90 triangle. 
This tells us that side AB = 9√3

Combining this info:
sin (C) = 9√3  ÷ 18  = √3 ÷ 2<span>
cos(B) = 9 </span>√3 ÷ 18 = √3 ÷ 2<span>
tan(C) = 9 </span>√3 ÷ 9 = √3<span>
sin(B) = 9 </span>÷ 18 = 1/2<span>
tan(B) = 9 </span>÷ 9√3 = 1 / √3 = √(3) ÷ 3
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Step-by-step explanation:

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180 - 59 = 121°

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The function f(x) = x3 – 8x2 + x + 42 has zeros located at 7, –2, 3. Verify the zeros of f(x) and explain how you verified them.
xeze [42]

Answer:

  • zeros are {-2, 3, 7} as verified by graphing
  • end behavior: f(x) tends toward infinity with the same sign as x

Step-by-step explanation:

A graphing calculator makes finding or verifying the zeros of a polynomial function as simple as typing the function into the input box.

<h3>Zeros</h3>

The attachment shows the function zeros to be x ∈ {-2, 3, 7}, as required.

<h3>End behavior</h3>

The leading coefficient of this odd-degree polynomial is positive, so the value of f(x) tends toward infinity of the same sign as x when the magnitude of x tends toward infinity.

  • x → -∞; f(x) → -∞
  • x → ∞; f(x) → ∞

__

<em>Additional comment</em>

The function is entered in the graphing calculator input box in "Horner form," which is also a convenient form for hand-evaluation of the function.

We know the x^2 coefficient is the opposite of the sum of the zeros:

  -(7 +(-2) +3) = -8 . . . . x^2 coefficient

And we know the constant is the opposite of the product of the zeros:

  -(7)(-2)(3) = 42 . . . . . constant

These checks lend further confidence that the zeros are those given.

(The constant is the opposite of the product of zeros only for odd-degree polynomials. For even-degree polynomials. the constant is the product of zeros.)

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Elena-2011 [213]

Answer:Yes i do

Step-by-step explanation:

Your welcome :)

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