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lilavasa [31]
4 years ago
6

Which trigonometric ratios are correct for triangle ABC? Check all that apply.

Mathematics
1 answer:
Alina [70]4 years ago
5 0
Assuming the - are bullet points and not negative signs:
sin = opposite/hypotenuse
cos = adjacent / hypotenuse
tan = opposite / adjacent. 
Also remember the special properties of the 30 - 60 - 90 triangle. 
This tells us that side AB = 9√3

Combining this info:
sin (C) = 9√3  ÷ 18  = √3 ÷ 2<span>
cos(B) = 9 </span>√3 ÷ 18 = √3 ÷ 2<span>
tan(C) = 9 </span>√3 ÷ 9 = √3<span>
sin(B) = 9 </span>÷ 18 = 1/2<span>
tan(B) = 9 </span>÷ 9√3 = 1 / √3 = √(3) ÷ 3
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I think the answer is first one, cost 235 and selling price 329

5 0
3 years ago
M1 Matrix is:
harkovskaia [24]

Answer:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

Step-by-step explanation:

Given matrix M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

The Inverse of a 2X2 matrix

A=\left(\begin{array}{ccc}a&b\\c&d\end{array}\right)

can be found using the following:

A^{-1}=\dfrac{1}{ad-bc} \left(\begin{array}{ccc}d&-b\\-c&a\end{array}\right)

Therefore:

M^{-1}=\dfrac{1}{(5*-5)-(3*-8)} \left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=-1\left(\begin{array}{ccc}5&-3\\8&-5\end{array}\right)\\=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)

Next, we find the product M^{-1}M

M^{-1}M=\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\left(\begin{array}{ccc}-5&3\\-8&5\end{array}\right)\\=\left(\begin{array}{ccc}-5*-5+3*-8&-5*3+3*5\\-8*-5+5*-8&-8*3+5*5\end{array}\right)\\=\left(\begin{array}{ccc}1&0\\0&1\end{array}\right)

Therefore:

(a)First Row, First Column =1

(b)First Row, second Column =0

(c)Second Row, First Column =0

(d)Second Row, second Column =1

NOTE: The multiplication of a matrix and its inverse always gives the identity matrix as seen above,

7 0
3 years ago
What is the slope of the table below?
Serjik [45]

Answer:

Where?

Step-by-step explanation:

Theres no picture to answer-

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3 years ago
Read 2 more answers
I'm stuck on this part of my pretest, I jut need to know where the correct angles go to.
Zolol [24]

Refer to the attachment :)

6 0
2 years ago
Elaborati un desen : punctul m este mijlocul bazei triunghiuluibisoscel abc
blondinia [14]
Uh .. Nu vorbesc limba română, dar am încercat meu cel mai bun pentru a face această întrebare.

Teorema: Fie ABC un triunghi isoscel cu AB = AC. Fie M denota punctul central al BC (adică, M este punctul pe BC pentru care MB = MC). Apoi
a) Triangle ABM este congruent cu ACM triunghi.
b) Unghi ABC = ACB Angle (unghiuri de bază sunt egale)
c) Unghi AMB = Unghi AMC = unghi drept.
d) Unghi BAM = unghiul CAM


Corolar: Prin urmare, din aceste fapte și definițiile:
Ray AM este unghiul bisectoarea unghiului BAC.Linia AM este altitudinea triunghiului ABC, prin A.Linia AM este mediatoare BSegmentul AM este mediana triunghiului ABC, prin A.Dovada # 1 din Teorema (după B & B)
Lasa bisectoarea unghiului de BAC se intersectează segmentul BC la punctul D.
Din moment ce raza AD este unghiul bisectoare, unghiul BAD = unghiul CAD.Segmentul AD = AD = sine.De asemenea, AB = AC deoarece triunghiul este isoscel.Astfel, triunghiul BAD este congruent cu CAD de SAS (side-unghi-side).
8 0
3 years ago
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