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saw5 [17]
3 years ago
15

Does anyone know this ?!!

Mathematics
2 answers:
Papessa [141]3 years ago
8 0

Answer:

all fractions can be written as a rational number like 1/5 it would be 0.2 its a rational number

Elodia [21]3 years ago
4 0

Answer:

im not 100% sure...but i think its integer

Step-by-step explanation:

i read on google

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Solve the quadratic equation using the Quadratic Formula: 3x2 +5x = 8. Arrange the steps in solving the equation.
victus00 [196]
0.2 i don’t know for sure
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3 years ago
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Lexi had 300 apples in her basket to sell if she dropped 122 apples on the ground she can't use them and sell them, and then aft
Andrew [12]

Answer:she has 120 apples left.

Step-by-step explanation:

Total number of apples that Lexi had in her basket to sell is 300.

If she dropped 122 apples on the ground because she can't use them and sell them, then the number of apples that she has left for sale is

300 - 122 = 178

If then after she sells 58 apples, the number of apples that she has remaining would be

178 - 58 = 120 apples

4 0
4 years ago
How many onions has shrek eaten
Illusion [34]

Answer:

alot

Step-by-step explanation:

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3 years ago
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A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium d
nikitadnepr [17]

Answer:

a) k=2.08 1/hour

b) The exponential growth model can be written as:

P(t)=Ce^{kt}

c) 977,435,644 cells

d) 2.033 billions cells per hour.

e) 2.81 hours.

Step-by-step explanation:

We have a model of exponential growth.

We know that the population duplicates every 20 minutes (t=0.33).

The initial population is P(t=0)=58.

The exponential growth model can be written as:

P(t)=Ce^{kt}

For t=0, we have:

P(0)=Ce^0=C=58

If we use the duplication time, we have:

P(t+0.33)=2P(t)\\\\58e^{k(t+0.33)}=2\cdot58e^{kt}\\\\e^{0.33k}=2\\\\0.33k=ln(2)\\\\k=ln(2)/0.33=2.08

Then, we have the model as:

P(t)=58e^{2.08t}

The relative growth rate (RGR) is defined, if P is the population and t the time, as:

RGR=\dfrac{1}{P}\dfrac{dP}{dt}=k

In this case, the RGR is k=2.08 1/h.

After 8 hours, we will have:

P(8)=58e^{2.08\cdot8}=58e^{16.64}=58\cdot 16,852,338= 977,435,644

The rate of growth can be calculated as dP/dt and is:

dP/dt=58[2.08\cdot e^{2.08t}]=120.64e^2.08t=2.08P(t)

For t=8, the rate of growth is:

dP/dt(8)=2.08P(8)=2.08\cdot 977,435,644 = 2,033,066,140

(2.033 billions cells per hour).

We can calculate when the population will reach 20,000 cells as:

P(t)=20,000\\\\58e^{2.08t}=20,000\\\\e^{2.08t}=20,000/58\approx344.827\\\\2.08t=ln(344.827)\approx5.843\\\\t=5.843/2.08\approx2.81

3 0
3 years ago
What is the coefficient of q in the sum of these two expressions?<br><br> (23q – 34) and (–16q – r)
Zigmanuir [339]

Answer:

The coefficient of q is 7

Step-by-step explanation:

The two expressions are

(23q – 34) and (–16q – r)

and .

(–16q – r)

The sum of the two expressions is

23q - 34 + -16q - r

When we group like terms the expression will be,

=23q - 16q - r - 34

When we  simplify the expression will now be

=7q - r - 34

The coefficient of q is the constant behind q in the expression.

The coefficient of q is therefore 7.

5 0
3 years ago
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