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svp [43]
3 years ago
12

Which equation could be used to find the height of the flagpole?

Mathematics
1 answer:
Andrew [12]3 years ago
6 0
Given a fragpole which makes a right angle with the point of observation with the angle of elevation as 50°.

Let x be the height of the flagpole, then

\sin50^o= \frac{x}{5}

Therefore, the <span>equation that could be used to find the height of the flagpole is
</span><span>x/5 = sin 50</span>
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Which points can be used in the diagram as the third vertex to create a right triangle with hypotenuse XY? Select all that apply
Pani-rosa [81]

Answer: (-2,-2)

(3,4)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help?!
Anton [14]

Answer:

Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider  the ratio of the sides

\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}            ..............( 1 )

\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}            ..............( 2 )

\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}            ..............( 3 )

So By equation ( 1 ), ( 2 ) and  ( 3 ) we get

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Now in Δ PQT  and Δ QRS we have

\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS  .....{S-S-S test for similarity}...Proved

8 0
3 years ago
Pls, Help I will mark brainliest and can you please show me working on how you did it,...I really need help
wolverine [178]

Answer:

Step-by-step explanation:

I think you just multiply 10 x 5 which equals 50 so both town's orignial population amount was 50%. I think ;-;

8 0
2 years ago
Amanda leaned a 15-foot ladder against the top of her house so she could get on the roof, which is 12 feet from the ground.
valentinak56 [21]

If you're trying to find the missing side of the "triangle" (the distance from the house to where the ladder touches the ground), you would use the pythagorean theorem, a²+b²=c². (c is always hypotenuse)

a²+b²=c²

12²+b²=15²

144+b²=225

b²=81

√b²=√81

b=9


8 0
3 years ago
What is the total measurement of a 30,20, degree intersecting variable of a acute triangle.
Ulleksa [173]
The measurement should be 130 according to my calculations
4 0
3 years ago
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