Answer:15+2.50(10x3)=x
Step-by-step explanation:
Corrected Question
Sue travels by bus or walks when she visits the shops. The probability that she catches the bus to the shops is 0.4. The probability she catches the bus from the shops is 0.7. Show the probability that Sue walks at one way is 0.72
Answer:
(Proved)
Step-by-step explanation:
Sue travels by bus or walks when she visits the shops.
Let the event that she catches the bus to the shop=A
Let the event that she catches the bus from the shop=B
P(A)=0.4
P(B)=0.7
Both A and B are independent events.
Therefore,Probability that she catches the bus to and from the shop:
P(A∩B) = 0.4 X 0.7= 0.28
Probability Sue walks at least one way 

Hence, the probability that Sue walks at least one way is 0.72.
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
|2y| = 3 + 2
− 2 (y+2) = 2 −y
x−2=4
Step-by-step explanation:
Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C
Answer:
3 + 4p + 8t
Step-by-step explanation:
3+2[2p+4t]
Distribute
3 + 4p + 8t
There are no like terms to combine