Answer:
Options A) and E)
Step-by-step explanation:
If you use Ruffini's method for polynomials, you can find the roots.
The given picture shows us the first root of the polynomial wich is 2.
Thus, the original polynomial can be written as
Here, you can notice that (x-2) is a factor
Answer:
A) None
Step-by-step explanation:
1) shoudnt neccesarily be a factor of nst, for example, if s = 3, t = 4, and n = 12, then both s and t are factors of n, but
is not a factor of nst = 144.
2) shoudnt neccesarily be a factor of nst. Let s be 4, let t be 6, and let n be 12. Then n is a factor of both s and t, but
is not a factor of nst = 12*24. In fact, it is a greater number.
3) Again, s+t isnt necessarily a factor of nst, let s be 2 and t be 3. Then both s and t are factor of n = 12. However 5 = s+t is not a factor of nst = 72.
So, neither of the three options is guaranteed to be a factor of nst. In fact, for s = 4, t = 6, and n = 12, none of the three options are valid.