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lora16 [44]
3 years ago
11

If Nina is N years old now and Maryna is M years old now, write… Four years ago, Nina was three times as old as Maryna was.

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer:

N - 4 = 3(M - 4). Simplified further, N - 4 = 3(M - 4)

Step-by-step explanation:

Given,

Nina is N years old now and;

Maryna is M years old now

If four years ago, Nina was three times as old as Maryna was, then

Four years ago, Nina's age was N - 4

Four years ago, Maryna's age was M - 4

Given that Nina was three times as old as Maryna was four years ago, it means that

N - 4 = 3(M - 4)

To solve further

N = 3m - 12 + 4

N = 3M - 8

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A car is towed using a force of 1600N. The rope used to pull the car makes an angle of 25∘ with the horizontal. Find the work do
mezya [45]

Answer: 2900185 Joules

Step-by-step explanation:

Force used to tow the car is 1600N

Angle(α)= 25

Displacement = 2km

Recall that 1km= 1000m

Therefore 2km= 2000m

Workdone= FdCos α

W= 1600 * 2000 * cos 25

W=2900184.919

W= 2900185 Nm(when approximated to the nearest integer)

Since 1J = 1Nm

Work done = 2900185 J

5 0
3 years ago
SOLVE AND EXPLAIN! b + m = 400?
kap26 [50]

Answer:

b=200 and m=200

Step-by-step explanation:

There are many answers to this problem. You can replace b and n for the number 200. You need to find what two numbers, added up, will give you 400. If b=200 and m=200, when added up, it will give you 400.

5 0
3 years ago
Determine which property is demonstrated below;
aniked [119]

Answer:

  symmetric property

Step-by-step explanation:

The <em>symmetric property</em> is the one that tells you A=B means also B=A.

The obfuscating factor in this question is the renaming of angle SZW to angle WZS. Both names refer to the same angle.

3 0
3 years ago
Approximate 218.16 to the nearest tens.
luda_lava [24]
218.16 to the nearest tenth would be 218
3 0
2 years ago
q(x)= x 2 −6x+9 x 2 −8x+15 ​ q, left parenthesis, x, right parenthesis, equals, start fraction, x, squared, minus, 8, x, plus, 1
AURORKA [14]

According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

<h3>What is the behavior of a functions close to one its vertical asymptotes?</h3>

Herein we know that the <em>rational</em> function is q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15), there are <em>vertical</em> asymptotes for values of x such that the denominator becomes zero. First, we factor both numerator and denominator of the equation to see <em>evitable</em> and <em>non-evitable</em> discontinuities:

q(x) = (x² - 6 · x + 9) / (x² - 8 · x + 15)

q(x) = [(x - 3)²] / [(x - 3) · (x - 5)]

q(x) = (x - 3) / (x - 5)

There are one <em>evitable</em> discontinuity and one <em>non-evitable</em> discontinuity. According to the theory of <em>rational</em> functions, there are no <em>vertical</em> asymptotes at the <em>rational</em> function evaluated at x = 3.

To learn more on rational functions: brainly.com/question/27914791

#SPJ1

8 0
1 year ago
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