Answer:
<h3>Your answer is 5.</h3>
<h3>7.7 - 3.11 = 4.59 = 5. (approx.)</h3>
False, 2/6 is less than 2/3
A) (3,2),(2,1)<br><br>
B) (3,-2),(-2,1)<br><br>
C) (-3,2),(-2,-1)<br><br>
D) (-3,-2),(2,-1)
bija089 [108]
Answer:
d
Step-by-step explanation:
Answer:
See explanation below
Step-by-step explanation:
The calculations for this lottery <em>do not involve </em>the combinations rule because <em>the order of the numbers does matter</em>. For example, 1234 and 4321 are different although they have the same digits.
The calculations for this lottery <em>do involve</em> the permutations with replacement rule because any selected number can be used more than once.
By <em>the fundamental rule of counting</em>, there are 10*10*10*10 = 10,000 possible outcomes of the event with a probability 1/10,000 = 0.0001 each outcome.
We have a sample that in fact represents the population.
We have to calculate the standard deviation of this population.
The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).
We have to start by calculating the mean of the population first:
Now, we can calculate the standard deviation as:
![\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%5B%5D%7B%5Cdfrac%7B1%7D%7Bn%7D%5Csum%5En_%7Bi%3D1%7D%5C%2C%20%28x_i-%5Cmu%29%5E2%7D)
![\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cdfrac%7B1%7D%7B6%7D%28%2837-34%29%5E2%2B%2838-34%29%5E2%2B%2839-34%29%5E2%2B%2840-34%29%5E2%2B%2839-34%29%5E2%2B%2811-34%29%5E2%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%283%5E2%2B4%5E2%2B5%5E2%2B6%5E2%2B5%5E2%2B%28-23%29%5E2%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%289%2B16%2B25%2B36%2B25%2B529%29%7D%20%5C%5C%20%5Csigma%3D%5Csqrt%5B%5D%7B%5Cfrac%7B1%7D%7B6%7D%28640%29%7D%20%5C%5C%20%5Csigma%5Capprox%5Csqrt%5B%5D%7B106.67%7D%20%5C%5C%20%5Csigma%5Capprox10.33%20%5Cend%7Bgathered%7D)
Answer: the standard deviation of this population is approximately 10.33
