Answer:
A baseball diamond is a square with sides of 90 feet. What is the distance to the nearest tenth of a foot between home and second base?
Step-by-step explanation:
127.3 feet This problem requires the use of pythagoras theorem. Ignore the face that it's a baseball diamond. All you're concerned with is that you have a square that's 90 feet per side and you want to know what the length of the diagonal. So you have a right triangle with 2 sides of 90 feet each and you want to know the length of the hypotenuse. The formula is C^2 = A^2 + B^2 Both A and B are 90, so plugging them into the formula gives C^2 = 90^2 + 90^2 = 8100 + 8100 = 16200 So C^2 = 16200 Take the square root of both sides C = 127.2792 Round to the nearest tenth, giving C = 127.3
Answer:
C
Step-by-step explanation:
Completing the square means
adding ( half the coefficient of the x- term )² to both sides, that is
( 
)² is added to both sides
Sphere Surface Area = <span> 4 • <span>π <span>• r²
For it to equal 16 PI, then radius must equal 2
4*PI*2*2 = 16 PI
</span></span></span>
Sphere Volume = <span> 4/3 • <span>π <span>• r³
</span></span></span>
Sphere Volume = <span> 4/3 • <span>π <span>• 2^3
</span></span></span>
Sphere Volume = <span> 4/3 *PI * 8
</span>
Sphere Volume = <span> 32 / 3 PI
</span>
Sphere Volume = <span> 10.666 PI cubic feet AND I think that is answer B
which SHOULD read 10 (2/3) PI ft^3
</span>
Hey user!
your answer is here..
we know about EULER'S FORMULA, it is a formula used to verify a polyhedron or to calculate the number of faces, vertices or edges.
Euler's formula = F + V - E = 2
given :-
faces = 28, verticies = 50 and edge = ?
we know that F + V - E = 2
therefore 28 + 40 - E = 2
==> 68 - E = 2
==> - E = 2 - 68
==> - E = - 66
==> E = 66
hence, the number of edges of the polyhedron is 66.
cheers!!
Answer:
4t
Step-by-step explanation:
Note that teach term has the variable t in it. Also, note that if t is by itself, it actually means 1t. Combine the given constants:
5t + 1t - 2t
= (5t + 1t) - 2t
= (6t) - 2t
= 4t
4t is your answer.
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