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Alik [6]
3 years ago
8

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 5, 0

Mathematics
2 answers:
qwelly [4]3 years ago
7 0

the correct answer is B.... on ED.....

just took the test....

Lunna [17]3 years ago
3 0
From looking at the image I've provided, you could see that the solution of that quadratic equation is -5 or 0.

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Find the following limit or state that it does not exist. ModifyingBelow lim With x right arrow minus 2 StartFraction 3 (2 x min
leva [86]

Answer:

-60

Step-by-step explanation:

The objective is to state whether or not the following limit exists

                                \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2}.

First, we simplify the expression in the numerator of the fraction.

3(2x-1)^2 -75 = 3(4x^2 - 4x +1) -75 = 12x^2 - 12x + 3 - 75 = 12x^2 - 12x -72

Now, we obtain

                         12(x^2-x-6) = 12(x+2)(x-3)

and the fraction is transformed into

                       \frac{3(2x-1)^2 - 75}{x+2} =  \frac{12(x+2)(x-3)}{x+2} = 12 (x-3)

Therefore, the following limit is

       \lim_{x \to -2}  \frac{3(2x-1)^2 - 75}{x+2} = \lim_{x \to -2}  12(x-3) = 12 \lim_{x \to -2} (x-3)

You can plug in -2 in the equation, hence

                        12 \lim_{x \to -2} (x-3) = 12 (-2-3) = -60

6 0
4 years ago
Which of the following is the conjugate of a complex number with 2 as the real part and −8 as the imaginary part?
vampirchik [111]
The complex number is given as: 2-8i

So for conjugate, you just flip the sign of the imaginary part:

2+8i will be the answer
3 0
3 years ago
Read 2 more answers
The ratio of a circle's radius to its diameter is always 1 to 2. In math class, Russell uses his compass to draw a circle with a
Semenov [28]

12 bc 6/12 equals 1/2

8 0
3 years ago
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A store is having a sale where movies are 15% off their original price a movie is sale for $22.10 what was the original price of
Alexus [3.1K]
The original price of the movie would be $26. Hope this helps!
6 0
3 years ago
Need help fast don't understand both A and B show work please
Shkiper50 [21]
Problem A
Usually the number of bits in a byte is 8 or 16 or 32 and recently 64. You don't have to write a formula to restrict it to this number of bits. You are not asked to do so. The general formula is 2^n - 1 for the problem of Millie and her golden keys. Somehow the system can be made to choose the right number of bits. Apple IIe s for example, used 8 bits and there was a location that told the processor that fact.

2^n - 1 <<<<< Answer

Problem B
In this case n = 4
2^n - 1 = 2^4 - 1 = 16 - 1 = 15


Millie can collect 15 keys <<<<<< Answer
5 0
3 years ago
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