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kramer
3 years ago
15

What is the distance between begin ordered pair 8 comma negative 3 comma 4 end ordered pair and begin ordered pair 6 comma negat

ive 4 comma 1 end ordered pair? Round to the nearest tenth of a unit.
Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer:

d = \sqrt{14} = 3.74...

Step-by-step explanation:

To find the distance between (8, -3, 4) and (6, -4, 1), use the distance formula for (x,y,z) points. It is very similar to (x,y) points.

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2 - z_1)^2} \\d = \sqrt{(8 - 6)^2 + (-3--4)^2 + (4-1)^2} \\d = \sqrt{(2)^2 + (1)^2 + (3)^2} \\d = \sqrt{4 + 1 + 9}\\ d = \sqrt{14} = 3.74...

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Step-by-step explanation:

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15/10=k

3/2=k

you can check with the next problem to check if it is the same

25=k(20)

25/20=k

5/4=k

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3 years ago
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3 years ago
270 american dollar and recevied 3000 pesos when he returned from mexico he had 100 pesos left. how many will he recevie when he
AURORKA [14]
To solve this problem we can use simple proportion
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270$ -------------------------3000 pesos
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7 0
3 years ago
Suppose you know that Mr. and Mrs. Vincent have at most eight children. One day you happen to meet two girls who were the Vincen
lianna [129]

Answer:

The number of children are 4 out of which 3 are girls

Step-by-step explanation:

Data provided in the question:

P(Two randomly selected children are girls) = \frac{1}{2}

now,

let the number of children be 'n'

the number of girls be 'x'

thus,

P(Two randomly selected children are girls) = \frac{^xC_2}{^nC_2} = \frac{1}{2}

also,

^nC_r = \frac{n!r!}{(n-r)!}

thus,

\frac{\frac{x!2!}{(x-2)!}}{\frac{n!2!}{(n-2)!}} = \frac{1}{2}

or

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2(3)(3-1) = 4(4-1)

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hence, the relation is justified

therefore,

The number of children are 4 out of which 3 are girls

3 0
3 years ago
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