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Vera_Pavlovna [14]

2 years ago

10

At the school store of magic, a wand costs 2.31$ Mr. WIzard wants to get a new wand for each of his 22 students. He has a $50 do

llar bill. Does Mr.Wizard have enough money? if yes, how much money will he have left? If no, how much more money will he need

1 answer:

mars1129 [50]2 years ago

4 0

2.31x 22 = 50.82

He needs 82 cents

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Use two points on the graph to find the slope of the line.

kap26 [50]

The function is y=x+2 so the slope of this function is 1

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2 years ago

Solve for x.<br><br><br><br> Enter your answer in the box.

rewona [7]

Answer:

x=61

Step-by-step explanation:

A 5 sided shape always has 540 degrees in angles in total. So, 540-90-107-144-138. Do this, and it gets you 61 degrees. Therefore x = 61 degrees

6 0

2 years ago

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

2 years ago

Help me please will be appreciated thx

alexandr1967 [171]

Answer:

-6 +8d -2c

Step-by-step explanation:

$\frac{-2}{5} (15 -20d +5c) = \frac{-2}{5} \times 15 - \frac{-2}{5}\times20d +\frac{-2}{5}\times5c = -6 + 8d -2c$

3 0

2 years ago

Help me answer these PLEASE ASAP

Hoochie [10]

Answer:

Answered below

Step-by-step explanation:

<u>Sheet 1: Question 3</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠LPN = ∠OPM

7 + 13x = -20 + 16x

27 = 3x

x = 9

<u>Sheet 1: Question 4</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠ABD = ∠EBC

2x + 20 = 3x + 15

-x = -5

x = 5

<u>Sheet 1: Question 5</u>

<u>Step 1: Find the value of x</u>

<em>Vertically opposite angles are equal so you will equate the angles given,</em>

∠SOP = ∠ROQ

5x = 4x + 10

x = 10

<u>Step 2: Find angles</u>

Angle SOP = 5x = 5(10) = 50°

Angle ROQ = 50° <em>(because it is vertically opposite to angle SOP)</em>

Angle SOR = 180 - 50 <em>(because all angles on a straight line are equal to 180°)</em>

Angle SOR = 130°

Angle POQ = 130° <em>(because it is vertically opposite to angle SOR)</em>

<u>Sheet 1: Question 6</u>

Angle 1 = 72° <em>(because vertically opposite angles)</em>

∠4 + ∠1 + 41 = 180° <em>(because all angles on a straight line are equal to 180°)</em>

∠4 + 72 + 41 = 180

∠4 = 67°

∠3 = 41° <em>(because vertically opposite angles)</em>

∠2 = 67° <em>(because vertically opposite angles)</em>

<u>Sheet 2: Question 3</u>

Step 1: Find the value of x

<em>Sum of complementary angles is equal to 90°</em>

Angle A + Angle B = 90°

7x + 4 + 4x + 9 = 90°

11x = 90 - 13

11x = 77

x = 7

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 7x + 4

7(7) + 4

Angle A = 53°

Angle B: 4x + 9

4(7) + 9

Angle B = 37°

<u>Sheet 3: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>Sum of supplementary angles is equal to 180°.</em>

Angle A + Angle B = 180°

3x - 7 + 2x + 2 = 180°

5x = 185

x = 37

<u>Step 2: Find angle A and angle B using x</u>

Angle A: 3x - 7

3(37)-7

Angle A = 104°

Angle B: 2x + 2

2(37) + 2

Angle B = 76°

<u>Sheet 3: Question 4</u>

<em>Sum of supplementary angles is equal to 180°.</em>

<u>Step 1: Find x</u>

1/4(36x-8) + 1/2(6x-20) = 180°

Take LCM

[36x - 8 + 2(6x - 20)]/4 = 180°

36x - 8 +12x - 40 = 180 x 4

48x - 48 = 720

48x = 768

x = 16

<em>Step 2: Find both angles with the help of x</em>

Angle 1: 1/4(36x-8)

1/4[36(16)-8] = 568/4

Angle 1 = 142°

Angle 2: 1/2(6x-20)

1/2[6(16)-20] = 76/2

Angle 2 = 38°

<u>Sheet 4: Question 1</u>

<em>All angles on a straight line are equal to 180°</em>

Angle z + 138° = 180°

Angle z = 180 - 138

Angle z = 42°

<u>Sheet 4: Question 2</u>

Linear pair 1: 5 and 7 <em>(because both angles are on a straight line and are equal to 180°)</em>

Linear pair 2: 6 and 8<em> (because both angles are on a straight line and are equal to 180°)</em>

<u>Sheet 4: Question 3</u>

<u>Step 1: Find the value of x</u>

<em>All angles on a straight line are equal to 180° or linear pairs are equal to 180°</em>

Angle LMO + Angle OMN = 180°

7x + 20 + 10 + 5x = 180°

12x = 180 - 30

x = 150/12

x = 12.5

<em>Step 2: Find angles using the value of x</em>

Angle LMO: 7x + 20

7(12.5) + 20

Angle LMO = 107.5°

Angle OMN: 10 + 5x

10 + 5(12.5)

Angle OMN = 72.5°

<u>Sheet 4: Question 4</u>

<em>Linear pairs are equal to 180°.</em>

Angle 1 + Angle 2 = 180°

1/3(27x-6) + 1/2(6x-20) = 180°

<em>Take LCM = 6</em>

[2(27x-6) + 3(6x-20)]/6 = 180

54x - 12 + 18x - 60 = 1080

72x - 72 = 1080

72x = 1152

x = 16

!!

7 0

3 years ago