Answer:
-16
Step-by-step explanation:
Given the sequence:
b(n)=b(n−1)−7, where b(1)=−2
b(2)=b(2−1)−7
=b(1)−7
=-2-7
b(2)=-9
Therefore, the 3rd term of the sequence
b(3)=b(3−1)−7
=b(2)-7 (Recall b(2)=-9 from above)
=-9-7
b(3)=-16
The 3rd term of the sequence is -16.

a. The gradient is


b. The gradient at point P(1, 2) is

c. The derivative of
at P in the direction of
is

It looks like

so that

Then


15% of R560 - 15% of R500
=> 0.15 × 560 – 0.15 × 500
=> 0.15 ( 560–500)
=> 0.15 × 60
=> Rs. 9
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Answer:
B
Step-by-step explanation:
Answer:
the answer is D which is 6