Step-by-step explanation:
the average rate of change of a function f in an interval [x-low, x-high] is
(f(x-high) - f(x-low)) / (x-high - x-low)
the year 2000 means t = 2000-1980 = 20
the year 2015 means t = 2015-1980 = 35
so, we have
(A(35) - A(20)) / (35 - 20)
((-0.6(35)² + 37.2×35 + 243) - (-0.6(20)² + 37.2×20 + 243)) / 15
((-735 + 1302 + 243) - (-240 + 744 + 243)) / 15
(810 - 747) / 15 = 63/15 = 4.2
the average change rate between 2000 and 2015 is 4.2.
that means that the use of nuclear energy in the USA increased by 4.2 billions of kilowatt hours per year during that period.
Answer:
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:

The statsitic would be given by:

Where O represent the observed values and E the expected values
The degrees of freedom are given by;

The significance level is 0.1 so then the critical value would be given by:

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Answer:
<h2>The value of y is <u>0.5</u>, so the answer is <u>C</u>.</h2>
Step-by-step explanation:
Find first the constant of variation.
Given: x = 3, y = 4
Find: k = ?
Formula:

Solution:

Then, find the value of y in the third box.
Given: x = 24, k = 12
Find: y = ?
Formula:

Solution:

Answer:
Answer is D
Step-by-step explanation:
I took the test and it is right because there are 2 chunks of dots in two spots
Answer:
40/3, 172/3, respectively
Step-by-step explanation:
x + 9 = 2y
2x = 2y + 2
x + 9 = 2(2x - 2)
4x - 4 = x + 9
3x - 13 = 0
x = 13/3
y = 40/6
RT = 13/3 + 9 = 40/3
QS = 160/3 + 4 = 172/3