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Lelu [443]
3 years ago
5

From home to school, Armen spent 36 minutes walking at a speed of 70 yards per minute. What was his speed, if he spent 8 minutes

less time while getting back?
Mathematics
1 answer:
hram777 [196]3 years ago
7 0

Answer:

  90 yards per minute

Step-by-step explanation:

Armen's time getting back was 36 -8 = 28 minutes. Then the ratio of times is 28/36 = 7/9.

The ratio of speeds is the inverse of this, so his speed coming back is ...

  speed/70 = 9/7

Multiplying by 70 gives ...

  speed = 70·9/7 = 90 . . . . yards per minute

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You plug 8 into where n is so it's 8-5
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NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

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For a vector

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A = a * b

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For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

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|u| = \sqrt{4 + 36}

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|v| = \sqrt{4^2+(-7)^2}

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cos\theta = \frac{-16}{\sqrt{2600}}

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\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

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