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3 years ago

How do you determine the circumference of a semicircle?

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

3 0

Circumference of a semicircle =

1/2(pi x radius^2) + diameter

Hope it helped :)

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What are the coefficients of each term in 4x -y -2x?

kifflom [539]

Answer:

4x and -2x

Step-by-step explanation:

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3 years ago

What are the factors of the expression (y-2)(x+3)

ivanzaharov [21]

(y-x) (2+3)= (yx)(5)
But am not sure it could be =(2-3) (y+x) = (1) (yx)

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4 years ago

Read 2 more answers

Ten years ago, only 20% of the u.s. population consisted of people more than 65 years old. a researcher plans to use a sample of

Strike441 [17]

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3 years ago

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Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

4(1-x) + 2x = -3( x + 1)

vlada-n [284]

Answer:

x = -7

Solution:

4(1-x) + 2x = -3( x + 1)

4(1 - x) + 2x = -3 (x + 1)

4(-x + 1) + 2x = -3 (x + 1)

-4x - 4 + 2x = -3(x + 1)

-2x + 4 = -3 (x + 1)

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3 years ago