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QveST [7]
3 years ago
15

On a number line, what is the distance between -8 and -2?

Mathematics
2 answers:
Harrizon [31]3 years ago
6 0

Answer:

6 units

Step-by-step explanation:

Distance between two points on the number lines, the difference between the absolute values.

I-8 I - I - 2I = 8 - 2 = 6

andrezito [222]3 years ago
3 0
<h2><u>Concept</u></h2>

The key to finding the distance between two points is to remember that the geometric definition of subtraction is the distance between the two numbers as long as we subtract the smaller number from the larger.

<h2><u>Solution</u></h2>

⇛(-8) - (-2)

⇛8 - 2

⇛6

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Evaluate: 7.921 x 10^4. ​
Sveta_85 [38]

Answer: 72,910

Step By Step Explaination:  7.291 x 10^4

10^4 means to move the decimal places four times.

7.921 = 79.210 = 792.10 = 7921.0 = 79,210

8 0
3 years ago
Use the function g(x) = -5x + 17 to answer the questions.
Kazeer [188]

Answer:

42

Step-by-step explanation:

g(-5)=-5.-5+17

=25+17

=42

3 0
3 years ago
Read 2 more answers
The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction
Len [333]

Answer:

(a) <em>                             </em><em>n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.

Assuming that the random variable <em>X </em>follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

  • For a sample size of <em>n</em> = 20

P(\mu-200

                                           =P(-0.37

  • For a sample size of <em>n</em> = 50

P(\mu-200

                                           =P(-0.59

  • For a sample size of <em>n</em> = 100

P(\mu-200

                                           =P(-0.83

  • For a sample size of <em>n</em> = 500

P(\mu-200

                                           =P(-1.86

<em>                                  n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample (\bar x) approaches the whole population mean (\mu_{x}).

Consider the probabilities computed in part (a).

As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.

So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.

Thus, the correct option is (b).

8 0
3 years ago
What is the product of 379 and 8
levacccp [35]
Product means multiplication, so I would multiply 379 and 8.
379 x 8 = 3032
<span>3032 is directly in between 3031 and 3033</span>
6 0
3 years ago
Read 2 more answers
What am I doing wrong? I've tried every conceivable answer, I thought I knew this type of math well, but this program keeps tell
Pachacha [2.7K]

Answer:

15.0 units

Step-by-step explanation:

Here, we want to get the distance between the two points as follows;

CD = √(x2-x1)^2 + (y2-y1)^2

So we have;

CD = √(7+8)^2 + (-5+4)^2

CD = √225+ 1 =

CD = √(226

CD = 15.0 units

8 0
3 years ago
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