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Alla [95]
3 years ago
7

Suppose a population consists of 50,000 people. Which of the following

Mathematics
1 answer:
vampirchik [111]3 years ago
6 0

Answer:

The number that would represent a sample statistic of a population but not a parameter is:

O A. Neither 500 nor 50,000

Step-by-step explanation:

The reason behind this is that a parameter has to follow a certain guideline because it needs to fulfill a rule to be considered one. There has to be a correlation, so if we have no clear establishment the number can't be a parameter. Thus, 500 would be the minimum 1% to be considered as a parameter and 50,000 the whole universe of the population. They keep a correlation, therefore any number but they would be a sample statistic.

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The cost to rent a rug-cleaning machine from the supermarket is $23 per day. The supermarket charges a check-out fee of $45 for
igomit [66]

Answer:

23d + 45 = 137

Explanation:

Since it is $23 per day, that dollar amount must be associated with a variable that multiples it per day that it is rented. Finally, you need to add the one time $45. This equation can then be used to find how many days it was rented for.

23d + 45 = 137

23d = 92 (Subtract 45 from both sides)

d = 4 (Divide by 23 on both sides)

The rug-cleaning machine was rented for 4 days. You found this using the equation: 23d + 45 = 137

8 0
3 years ago
Prove by mathematical induction that
postnew [5]

For n=1, on the left we have \cos\theta, and on the right,

\dfrac{\sin2\theta}{2\sin\theta}=\dfrac{2\sin\theta\cos\theta}{2\sin\theta}=\cos\theta

(where we use the double angle identity: \sin2\theta=2\sin\theta\cos\theta)

Suppose the relation holds for n=k:

\displaystyle\sum_{n=1}^k\cos(2n-1)\theta=\dfrac{\sin2k\theta}{2\sin\theta}

Then for n=k+1, the left side is

\displaystyle\sum_{n=1}^{k+1}\cos(2n-1)\theta=\sum_{n=1}^k\cos(2n-1)\theta+\cos(2k+1)\theta=\dfrac{\sin2k\theta}{2\sin\theta}+\cos(2k+1)\theta

So we want to show that

\dfrac{\sin2k\theta}{2\sin\theta}+\cos(2k+1)\theta=\dfrac{\sin(2k+2)\theta}{2\sin\theta}

On the left side, we can combine the fractions:

\dfrac{\sin2k\theta+2\sin\theta\cos(2k+1)\theta}{2\sin\theta}

Recall that

\cos(x+y)=\cos x\cos y-\sin x\sin y

so that we can write

\dfrac{\sin2k\theta+2\sin\theta(\cos2k\theta\cos\theta-\sin2k\theta\sin\theta)}{2\sin\theta}

=\dfrac{\sin2k\theta+\sin2\theta\cos2k\theta-2\sin2k\theta\sin^2\theta}{2\sin\theta}

=\dfrac{\sin2k\theta(1-2\sin^2\theta)+\sin2\theta\cos2k\theta}{2\sin\theta}

=\dfrac{\sin2k\theta\cos2\theta+\sin2\theta\cos2k\theta}{2\sin\theta}

(another double angle identity: \cos2\theta=\cos^2\theta-\sin^2\theta=1-2\sin^2\theta)

Then recall that

\sin(x+y)=\sin x\cos y+\sin y\cos x

which lets us consolidate the numerator to get what we wanted:

=\dfrac{\sin(2k+2)\theta}{2\sin\theta}

and the identity is established.

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2 years ago
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Fynjy0 [20]
(5x^2 - 7)(5x^2 + 7)
(5x^2)^2 - 7^2
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Answer:
25x^4 - 49

Hope this helps.
3 0
2 years ago
Read 2 more answers
Line m has a slope of -3. Another line n is parallel to line m. What is the slop of line n?
mina [271]

Answer:

I think its also -3

because its parallel

7 0
3 years ago
A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed
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21499 +12*x=22.75*x
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3 years ago
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