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3 years ago

What is the solution for y=4x−9

1 answer:

7 0

To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

x-intercept: (9/4,0)

y-intercept: (0,−9)

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4. Which graph represents the solution to<br> -2<3x+1 ?<br>

dalvyx [7]

Hey there!

-2<3x+1

= 3x + 1 < -2

SUBTRACT 1 to BOTH SIDES

3x + 1 - 1 < -2 + 1

CANCEL out: 1 - 1 because that gives you 0

KEEP: -2 + 1 because that helps you solve for x

-2 + 1 = -3

New EQUATION: 3x > -3

DIVIDE 3 to BOTH SIDES

3x/3 > -3/3

CANCEL out: 3/3 because that gives you 1

KEE3 -3/3 because that helps us compare for x

-3/3 = -1

Answer to the equation: x > -1

OVERALL Answer: x > -1; It is an OPENED circle shaded to the right starting at -1 (Option A.)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 0

2 years ago

Find all the factors of 45

scoundrel [369]

Answer:

So, the factors of 45 are 1, 3, 5, 9, 15 and 45.

Common Factors.

Prime Numbers.

Highest Common Factor.

Step-by-step explanation:

45 is a composite number. 45 = 1 x 45, 3 x 15, or 5 x 9. Factors of 45: 1, 3, 5, 9, 15, 45. Prime factorization: 45 = 3 x 3 x 5, which can also be written 45 = 3² x 5.

8 0

2 years ago

which two points should the line of best fit go through to best represent the data in the scatter plot (1,16) and (2,15) (1,16)

Rashid [163]

You simply have to plot the point and draw a line that passes through most of them

6 0

2 years ago

Read 2 more answers

The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. What is the point-slope fo

ser-zykov [4K]

Point slope form: $y-y₁=5(x-x₁)$

$y+13=5(x+2)$

6 0

3 years ago

Please answer the questions

Naily [24]

Answer:

1/18

Step-by-step explanation:

$( {2}^{ - 3} \times {16}^{ \frac{1}{2} } ) \div ( {81}^{ \frac{3}{4} } \times {27}^{ - \frac{1}{3} } ) \\ \\ =( {2}^{ - 3} \times {2}^{ \frac{4 \times 1}{2} } ) \div ( {3}^{ \frac{4 \times 3}{4} } \times {3}^{ - \frac{3 \times 1}{3} } ) \\ \\=( {2}^{ - 3} \times {2}^{ 2} ) \div ( {3}^{ 3 } \times {3}^{ - 1 } ) \\ \\=( {2}^{ - 3 + 2} ) \div ( {3}^{ 3 - 1 } ) \\ \\ = {2}^{ - 1} \div {3}^{2} \\ \\ = \frac{1}{2} \times \frac{1}{9} \\ \\ = \frac{1}{18}$

5 0

2 years ago