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madam [21]
4 years ago
12

Three sections of a fence need to be painted. Each section of the fence is made of 4 equal-sized boards. Alex paints 1/6 of the

fence. Bobby paints twice as much as Alex. Charles paints only 1 board. David paints the rest. Part A: Who paints the largest part of the fence? Part B: What fraction of the fence did he paint?
Mathematics
1 answer:
zepelin [54]4 years ago
3 0
Part A:

Total boards = 3 sections of 4 boards = 12 boards

Alex paints: 1/6 of 12 boards = 2 boards

Bobby paints: 2 x Alex = 1/3 of 12 boards = 4 boards

Charles paints: 1 board

David paints: 12 - (Alex + Bobby + Charles) = 12 - 7 = 5 boards

-This means that David painted the largest part of the fence

Part B:

The fraction of the fence that David painted = 5 boards /12 total boards = 5/12
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