Answer:
Option 2
Step-by-step explanation:
First, find the slope of the line of the graph using the points given as (5, -3) and (13, -9):

Any of the triangle in the options given, whose opp side has the same slope value of -¾, is the triangle we are looking for.
Option 1: slope between the points (0, 2) and (3, -2).

Option 2: slope between the point (-7, 6) and (-3, 3).

Option 2 has the same slope as the one given in the graph. This is the answer.
Option 3: slope between the points (5, -1) and (2, -5).

Option 4: slope between the points (2, -7) and (6, -4).

The answer is Option 2
The answer is the parallel line to one of a triangle.
Answer:
9 , 4 , 1 , 2
Step-by-step explanation:
Given that Hiro picked up 4 digit cards and the cards will make Multiple of 10
The numbers on the digit cards that will most likely make Multiple of 10 are :
9 , 4 , 1 , 2
You need to find the acceleration once the rope starts acting.
For that, first you need the velocity, V, when Karen ends the 2.0 m free fall
V^2 = Vo^2 + 2gd = 0^2 + 2* 9.81m/s^2 * 2.0 m = 39.24 m^2 / s^2 => V = 6.26 m/s
From that point, the rope starts acting with a net force that produces a constant acceleration, modeled as per these values and equation:
Vo = 6.26m/s
Vf = 0
Vf^2 = Vo^2 + 2ad => a = [Vf^2 - Vo^2] / 2d = [0^2 - (6.26 m/s)2 ] /2(1m) = -19.62 m/s^2
That acceleration is due to the difference of the force applied by the rope - the weight of Karen:
Weight of Karen: mg
Weight of karen - Force of the rope = Net force = ma
mg - Force of the rope = ma
Force of the rope = mg - ma = m(g -a) = m [9.81m/s^2 - (-19.62m/s^2) ]= 29.43m
To express it as a multiple of her weight, divide it by her weight (mg = 9.81m) =>
29.43m / 9.81m = 3.0
Answer: 3.0 times.