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AVprozaik [17]
3 years ago
5

Find 2 consecutive even integers such that twice the larger integer is four more than half of the smaller integer

Mathematics
1 answer:
solong [7]3 years ago
6 0

Answer:

0 and 2

Step-by-step explanation:

Let the two consecutive integers be 2x and 2x+2

We are given that twice the larger integer is four more than half of the smaller integer

2(2x+2)=\frac{1}{2}(2x)+4

4x+4=x+4

x=0

So, Two consecutive integers are 2(0)=0 and 2(0)+2=2

Hence the two consecutive integers are 0 and 2

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Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.
Vesna [10]

You're looking for the largest number <em>x</em> such that

<em>x</em> ≡ 1 (mod 451)

<em>x</em> ≡ 4 (mod 328)

<em>x</em> ≡ 1 (mod 673)

Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0
3 years ago
PLEASE HELP ASAP <br>will mark brainliest​
GREYUIT [131]

Answer:

7

Step-by-step explanation:

7-7=0 and this cannot happen in the denominator

4 0
3 years ago
Read 2 more answers
What is the Pythagorean’s Theorem ?
mr Goodwill [35]
A^2 + b^ = c^2

c is the longest side of the triangle
a and b are the other two sides

So the given are the hypotenuse leg, and one of the other legs

So
a= ?
b= 12
c= 14

a^2+12^2=14^2

a^2+144=196
-144 -144

a^2=52

So we find the square root of 52

Which is 7.211 which you can round to 7.21 or 7.2

4 0
3 years ago
Use the graph that shows the solution to f(x)=g(x).
madreJ [45]

Answer:

-2

Step-by-step explanation:

if showing in graph would be minus 2

8 0
3 years ago
Simplify this radical.<br> V84
Yanka [14]

Answer:

2\sqrt{21}

Step-by-step explanation:

84/4=21

Square root of 4=2

2\sqrt{21}

8 0
3 years ago
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