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Savatey [412]
3 years ago
14

A department store sells a pair of shoes with an 87% markup. If the store bought the pair of shoes for $55.25, what is the selli

ng price to the nearest dollar? A. $87 B. $103 C. $142 D. $187
Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0
Markup means they sell it for that percentage more than they bought it for. First let's calculate how much they will mark it up for:

\sf 55.25\cdot 87\%

Convert 87% into a decimal(87/100):

\sf 55.25\cdot 0.87

Multiply:

\sf\approx 48

This is how much they'll mark it up, now let's add it to how much they bought it for to find out the selling price:

\sf 48+55.25\approx\boxed{\sf \$ 103}
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A bacteria culture initially contains 100 cells and grows at a rate proportional to its size. After an hour the population has i
bija089 [108]

Answer: \bold{a)\ P(t)=P_o\cdot e^{t\cdot ln(2.7)}}

               b) 5314

               c) ln 2.7

               d) 4.6 hrs

<u>Step-by-step explanation:</u>

P(t) = P_o\cdot e^{kt}\\\\\bullet \text{P(t) is the number of bacteria after t hours} \\\bullet P_o\text{ is the initial number of bacteria}\\\bullet \text{k is the rate of growth}\\\bullet \text{t is the time (in hours)}\\\\\\270=100\cdot e^{k(1)}\\2.7=e^k\\ln\ 2.7=\ln e^k\\\boxed{ln\ 2.7=k}\\\\\text{So the equation to find the number of bacteria is: }\boxed{P(t)=P_o\cdot e^{t\cdot ln(2.7)}}\\\\\\P(4)=100\cdot e^{4\cdot ln(2.7)}\\.\qquad =\boxed{5314}

10,000=100\cdot e^{t\cdot ln(2.7)}\\100=e^{t\cdot ln(2.7)}\\ln\ 100=ln\ e^{t\cdot ln(2.7)}\\ln\ 100=t\cdot ln(2.7)\\\dfrac{ln\ 100}{ln\ 2.7}=t\\\\\boxed{4.6=t}

4 0
3 years ago
Which similarity transformation could map △DEF to △D'E'F'? A) dilation and reflection B) dilation and translation C) rotation an
aliya0001 [1]
C is correct
(im taking quiz)
6 0
3 years ago
Read 2 more answers
The dimensions of the tank are 50 cm by 32 cm by 20 cm. The tank is full of water and sand. The ratio of the volume of water to
Sauron [17]

Given:

Dimensions of a tank are 50 cm by 32 cm by 20 cm

The tank is full of water and sand

Ratio of volume of water to the volume of sand is 5:1

To find:

Volume of water in the tank in liters

Solution:

Without loss of generality, let,

Length of tank = 50 cm

Breadth of tank = 32 cm

Height of tank = 20 cm

Then, we have,

Total Volume of the tank = Length * Breadth * Height

\Rightarrow Total Volume = 50*32*20 cc

\Rightarrow Total Volume = 32000 cc

It is given that,

Volume of water : Volume of sand = 5:1

\Rightarrow (Volume of water)/(Volume of sand) = 5/1

Cross multiplying, we have,

Volume of sand = (Volume of water)/5

It is also given that the tank is full of water and sand. This implies that,

Volume of water + Volume of sand = Total Volume

Using the value, we obtained, we get,

Volume of water + (Volume of water)/5 = Total Volume

\Rightarrow (6 * Volume of water)/5 = Total Volume

Plugging in the value of total volume, we get,

\Rightarrow (6 * Volume of water)/5 = 32000 cc

\Rightarrow Volume of water = \frac{32000*5}{6} cc

\Rightarrow Volume of water \approx 26,666.6667 cc

We know that,

1 cc = 0.001 liters

\Rightarrow 26,666.6667 cc = (26666.6667 * 0.001) liters

\Rightarrow 26,666.6667 cc \approx 26.667 liters

Thus, Volume of water in the tank is approximately 26.667 liters

Final Answer:

Volume of water in the tank (in liters) is approximately 26.667 liters

4 0
3 years ago
Help can some one do number 10 please
marissa [1.9K]
Download Socratic it'll do everything
6 0
3 years ago
Suppose it takes John 18 minutes to run 3 miles. How long would it take him to run 7 kilometers? round to the nearest minute
alex41 [277]

Answer: 26 Minutes

Step-by-step explanation:

3 mi * 1.609 km/1 mi = 4.82 km

4.82 km/ 18 minutes = 7 km/ x minutes

4.82x=18*7

x=126/4.82

x=26.14 ~ 26 Minutes

8 0
3 years ago
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