If within the year 2014, the population p of the rabbits m months after January 2014 is modeled by the equation p = 0.05(m-1.5)(m-8.5) and the population reach 10,000 some time in February, to determine the time, given as months after January 1 2014, that the rabbit population reach ten thousand, we will substitute p = 10 into the modeled equation and get the value of m as shown;

$p = 0.05(m-1.5)(m-8.5)+10 \\substitute \ p = 10\\\\ 10 = 0.05(m-1.5)(m-8.5)+10\\\\10-10 = 0.05(m-1.5)(m-8.5)\\\\0 = 0.05(m-1.5)(m-8.5)\\\\0/0.05 = (m-1.5)(m-8.5)\\\\0 = (m-1.5)(m-8.5)\\ (m-1.5)(m-8.5) = 0\\ m-1.5 = 0 \ and \ m-8.5 = 0\\m = 1.5 \ and \ 8.5\\$

Hence the population of the rabbit reach 10,000 after 1.5 months and 8.5 months

5 0

3 years ago

What strategy would be the best to solve this problem?

marysya [2.9K]

Answer:

look for patterns also, Ann purchased 12 apples

Step-by-step explanation:

x apples

1/3 of x, (x - x/3) = (3x - x) /3 = 2x/3

Number of people who shared (2x/3) = 4 with each getting 2Total number shared = 4 * 2 = 8Fraction shared = total shared2x/3 = 8Multiply both sides by 3(2x/3) * 3 = 8 * 32x = 24x = 12

6 0

2 years ago

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