Question

IF y varies directly as x , and y is 6 when x is 72, what is the value of y when x is 8

Answer 1

Y=kx, k is not equal to 0
when y=6, x=72, 6=72k
                            k=1/12
so y=1/12*x
when x=8, y=1/12*8=2/3

Answer 2

Answer:

$y=\frac{2}{3}$

Step-by-step explanation:

It has been given that y varies directly as x

Thus, we have

y = kx, where k is constant of proportionality.

Now, y = 6, x = 72.

Substituting these values in above equation and find k

$6=72k$

Divide both sides by 72

$k=\frac{6}{72}\\\\k=\frac{1}{12}$

Now, we have to find y when x = 8

$y=\frac{1}{12}\times8\\\\y=\frac{2}{3}$

Therefore, the value of y is $\frac{2}{3}$