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2 years ago

7

Write a pair of equivalent expressions using distributive property

1 answer:

bulgar [2K]2 years ago

7 0

The distributive property "distributes" a number through all numbers/terms in a set of parentheses by multiplication.

EXAMPLES
Equivalent expressions are the first and last steps. The middle step just shows the work.

5(2 + 3x)= (5*2) + (5*3x)= 7 + 15x

4(2x + 4y)= (4*2x) + (4*4y)= 8x + 16y

10(4x + 5)= (10*4x) + (10*5)= 40x + 50

ANSWER:
Only one pair below is needed for your answer.

5(2 + 3x)= 7 + 15x

4(2x + 4y)= 8x + 16y

10(4x + 5)= 40x + 50

Hope this helps! :)

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Which of these equations are linear functions that go

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Answer:

I don't think the answer exist

Step-by-step explanation:

for y=6x

when y=0, x=0 and when x=0, y=0

hence, (x,y)=(0,0)

for y=x+6

when y=0, x+6=0, x=-6 and when x=0, y=6

hence (x,y) = (-6,6)

for y=x^2+6

when x=0, y=6 and when y=0,

x^2+6=0

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x^2=-6

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3 years ago

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3 years ago

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

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Step-by-step explanation:

<em><u>The question is</u></em>

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

so

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

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