Answer:
I don't think the answer exist
Step-by-step explanation:
for y=6x
when y=0, x=0 and when x=0, y=0
hence, (x,y)=(0,0)
for y=x+6
when y=0, x+6=0, x=-6 and when x=0, y=6
hence (x,y) = (-6,6)
for y=x^2+6
when x=0, y=6 and when y=0,
x^2+6=0
subtracting 6 from both sides
x^2=-6
take the square root of both sides and get
x=+ or -sqrt(-6)= + or - (2.45i)
i.e. x=+2.45i or x=-2.45i these are complex roots anyway, and its out of point.
for y=2x+6
when x=0, y=6 and when y=0,
2x+6=0,
2x=-6,
x=-3
the coordinates give (x,y)=(-3,6)
conclude....
The answer is e
reeeeeeeeeeee
Answer:

The domain for x is all real numbers greater than zero and less than 5 com
Step-by-step explanation:
<em><u>The question is</u></em>
What is the volume of the open top box as a function of the side length x in cm of the square cutouts?
see the attached figure to better understand the problem
Let
x -----> the side length in cm of the square cutouts
we know that
The volume of the open top box is

we have



substitute

Find the domain for x
we know that

so
The domain is the interval (0,5)
The domain is all real numbers greater than zero and less than 5 cm
therefore
The volume of the open top box as a function of the side length x in cm of the square cutouts is
