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Mathematics

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Bas_tet [7]3 years ago

4 0

I would say 25 is the answer to it

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y=f(x) is odd (f(-x)=-f(x)) and f(x>0) = x^2-5x-12, x is not = to 0. What points does the line f(x)=12 go through.

solmaris [256]

<span>f(x<0)=-f(x>0)=-x^2+5x+12 When x>0, x^2-5x-12=12, x=8, y=12 Therefore, f(x)=12 goes through point (8,12).</span>

5 0

3 years ago

Help please I'm almost done

LUCKY_DIMON [66]

Simple....

3x-10(x+2)=13-7x

Just solve for x.....

3x-10x-20=13-7x

-7x-20=13-7x
+7x +7x

-20=13

NO SOLUTION.

Thus, your answer.

6 0

3 years ago

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I need help on these problems

VikaD [51]

Someone is writing the answer so ill just give you this tip for whenever.
A negitive times a negitive is positive
a negative times a positive is negitive
and a positive times a positive is positive (just had to add it to be complete)

8 0

3 years ago

You wonder how many cars there are in your area. You call up the Ford dealership and ask how many Fords they’ve sold. They repor

SVETLANKA909090 [29]

If we take 1200 as the 100%, how much percentage is 700 of it?

well $\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1200&100\\
700&x
\end{array}\implies \cfrac{1200}{700}=\cfrac{100}{x}\implies x=\cfrac{700\cdot 100}{1200}
\\\\\\
x=\cfrac{175}{3}$

so, (175/3)% or roughly 58.3%

now, how much is (175/3)% of 15000 ?
well, if we take 15000 as the 100%
then $\bf \begin{array}{ccllll}
amount&\%\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
15000&100\\
x&\frac{175}{3}
\end{array}\implies \cfrac{15000}{x}=\cfrac{100}{\frac{175}{3}}
\\\\\\
\cfrac{15000\cdot \frac{175}{3}}{100}=x\implies \cfrac{5000\cdot 175}{100}=x$

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D%20%3D%20%5Cfrac%7Bx%7D%7B11%7D" id="TexFormula1" title="\frac{8}{3} = \f

Yuri [45]

The answer should be X= 88/3 or x= 29 1/3

4 0

2 years ago

Read 2 more answers