Answer:
FALSE
Step-by-step explanation:
<E in ∆AED ≅ <E in ∆CEB.
Both are 90°.
Side ED ≅ Side EB
Side AD ≅ Side CB.
Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.
For angles in first quadrant, the reference angle is itself. In second quadrant, the equation would be 180 - x where x is the measure of the angle. In third quadrant, x - 180. Lastly, in the fourth quadrant, the reference angle is 360 - x. From the second set of angles in the given, the reference angles are.
(1) 135 ; RA = 180 - 135 = 45
(2) 240; RA = 240 - 180 = 60
(3) 270; RA = 90 (lies in the y - axis)
(4) 330; RA = 360 - 330 = 30
Answer:
LN = 64 units
Step-by-step explanation:
Given M lies on LN, so LN = LM + MN --------------(1)
LN = 12x + 16
LM = 10x + 8
MN = 5x - 4
Substituting the values in equation 1, we get:
12x + 16 = (10x + 8) + (5x - 4)
12x + 16 = 15x + 4
15x - 12x = 16 -4
3x=12
Therefore x=4
LN= 12(4) + 16 = 64 units
Answer:
44.0
Step-by-step explanation:
Mark me as brainliest
Answer:
y = 2x + -5
Step-by-step explanation:
If you look at the graph, you can find that the slope is 2/1 which is simply just a slope of 2. The y-intercept can be found x = 0, so plug in 0 for x, solve from there and you get -5 for the y-intercept.
