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ruslelena [56]
3 years ago
5

The equation of the circle whose center is at (2,1) and the radius is 3 is

Mathematics
1 answer:
-BARSIC- [3]3 years ago
8 0

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{2}{ h},\stackrel{1}{ k})\qquad \qquad radius=\stackrel{3}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-2)^2+(y-1)^2=3^2\implies (x-2)^2+(y-1)^2=9

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Answer:

10n = d

Step-by-step explanation:

We know that

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svetoff [14.1K]

Answer:

Step-by-step explanation:

This is a quadratic expression.  Use the quadratic formula to find the roots, and then once you have the roots, write the corresponding factors.

The coefficients of this quadratic expression are a = 7, b = 5 and c = -3

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Using the quadratic formula, we now find these roots:

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x = --------------------------------   which here is:

                   2a

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x = -----------------

             14

The factors can be found from these two roots.  The first one is

      -5 - √109                  5 + √109

(x - ---------------- )  =  (x + ---------------- )

             14                              14

and the second is

        5 - √109              

(x + ---------------- )  

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8 0
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