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3 years ago

129 -21x + 8 -9x + 13 -2

Mathematics

2 answers:

erastovalidia [21]3 years ago

6 0

Answer:

-30 x +148

Step-by-step explanation:

<em>MARK BRAINLIEST!</em>

Gelneren [198K]3 years ago

6 0

Answer: 148 - 30x

Step-by-step explanation:

129 - 21x + 8 - 9x + 13 - 2

Combine like terms

129 + 8 + 13 - 2 - 21x - 9x

148 - 30x

I hope this helps.

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3 years ago

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zheka24 [161]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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2 years ago

Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

zmey [24]

Answer:

$\sin \theta = \dfrac{5}{13}$ and $\sec \theta = -\dfrac{13}{12}$

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

$hypotenuse^2=(5)^2+(12)^2$

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Taking square root on both sides.

$hypotenuse=13$

In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

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$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

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4 years ago

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3 years ago