Answer:
something
Step-by-step explanation:
1. 0.91<0.93; 0.91 is farther away from the whole number 1 so it is less than 0.93.
2. 0.5=0.50; 0.5 and 0.50 are the same, since the decimal can be written with or without the zero.
3. 1.08<1.6; 1.08 is farther away from the whole number 2, so it is less than 1.6.
Answer: The running time should at least 119.32 seconds to be in the top 5% of runners.
Step-by-step explanation:
Let X= random variable that represents the running time of men between 18 and 30 years of age.
As per given, X is normally distrusted with mean 
and standard deviation 
.
To find: x in top 5% i.e. we need to find x such that P(X<x)=95% or 0.95.
i.e. 
Since, z-value for 0.95 p-value ( one-tailed) =1.645
So,
Hence, the running time should at least 119.32 seconds to be in the top 5% of runners.
Answer:
Domain = R- {0,4}
Step-by-step explanation:
In order to function (f*g)x to be defined , the Denominator must not be equal to zero.
Hence
x ≠ 0
(x-4) ≠ 0 ⇒ x≠4
Hence (f*g)x is defined for all values of x except 0 and 4
Hence Domain = R- {0,4}
Answer:
The length of diagonal BD is 11·(1 + √3)
The length of diagonal AC = 22
Step-by-step explanation:
The given data are;
Quadrilateral ABCD = A kite
The length of segment AD = 22
The measure of ∠DAE = 60°
The measure of ∠BCEE = 45°
Whereby, triangle ΔADE = A right triangle, and DE is the perpendicular bisector of AC, by trigonometric ratio, we have;
AE = EC
DE = 22 × sin(60°) = 11·√3
AE = 22 × cos(60°) = 11
∴ AE = EC = 11
BE = EC × tan(∠BCE) = 11 × tan(45°) = 11
The length of the diagonal BD = BE + DE (By segment addition property)
∴ BD = 11 + 11·√3 = 11·(1 + √3)
The length of diagonal BD = 11·(1 + √3)
The length of diagonal AC = AE + EC
∴ AC + 11 + 11 = 22
The length of diagonal AC = 22.
