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3 years ago

What is the third term in the expansion of the binomial (2x 5)5?

1 answer:

6 0

Hello,
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1

(2x+5)^5=1*(2x)^5+5*(2x)^4*5+10*(2x)^3*5^2+10*(2x)^2*5^3+5*(2x)*5^4+5^5

Third term is 10*8*x^3*25=2000 x^3

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2x- 3y=9 5x+3y=12 How would i solve this? I dont understand this and i really need help with it!Also I have to graph the an

dedylja [7]

$\begin{cases} 2x- 3y=9 \\5x+3y=12 \end{cases}\\ + \ \ ------- \\ 7x=21 \ \ /: 7\\ \\x=\frac{21}{3}\\ \\ x=3 \\ \\2x- 3y=9$

$2*3-3y=9\\ \\6-3y =9\\ \\-3y=9-6\\ \\-3y=3 \ \ / :(-3)\\ \\x=-1\\ \\ \begin{cases} x=3\\y= -1 \end{cases}$

$graph\\ \\\begin{cases} 2x- 3y=9 \\5x+3y=12 \end{cases}\\ \\ \begin{cases} - 3y=-2x+9\ \ /:(-3) \\ 3y=-5x+12 \ \ /:3 \end{cases}\\ \\ \begin{cases} y= \frac{2}{3}x-3 \\ y=-\frac{5}{3}x+4 \end{cases}$

7 0

3 years ago

Find the distance between<br> (-1, - 3) and (8, – 3).

dimaraw [331]

Answer: d (A,B) = 9

Step-by-step explanation: d(A,B) = √(xB - xA)^2 + (yB - yA)^2

d(A,B) = √(8-(-1))^2 + (-3 - (-3))^2

d(A,B) = √81 + 0

d(A,B) = 9

5 0

3 years ago

The diagram shows a sector of a circle radius 10cm

Yuki888 [10]

Answer:

$\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}$

Step-by-step explanation:

$\text{Perimeter of the sector = Radius + arc length + radius}$

$\text{Radius = 10 cm}$

$\text{Perimeter of the sector = 10 + arc length + 10 }$

$\text{Perimeter of the sector = 20 + arc length }$

$\text{arc length = (sector angle/ 360 ) * perimeter of the circle}$

$\text{Perimeter of a circle }=2\pi r$

$\text{sector angle} = 135$

$\text{arc length} = (135/ 360 ) * 2\pi (10)$

$= (3/8) 20\pi$

$= 15\pi /2$

$\text{Using }\pi =3.14$

$= 15 * 3.14 /2$

$= 23.55$

$\text{Perimeter of the sector = 20 + 23.55}$

$= 43.55$

$= 43.6 cm$

$\text{perimeter of the sector = 43.6 cm }$

8 0

2 years ago

The bases of the trapezoid are 6 and 10. The height is 4. Find the area.

kari74 [83]

<h2>Answer:</h2>

$b. \ \boxed{32 \sq. \ units}$

<h2>Step-by-step explanation:</h2>

A trapezoid is a quadrilateral where at least one pair of opposite sides are parallel. In a trapezoid, the both parallel sides are known as the bases of the trapezoid. So we have two bases, namely, $b_{1}\,and\,b_{2}$ . Also, the height $H$ of the trapezoid is the length between these two bases that's perpendicular to both sides. So the area of a trapezoid in terms of of $b_{1},b_{2}\:and\:H$ is: