What is the third term in the expansion of the binomial (2x 5)5?

1 answer:

6 0

Hello,
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1

(2x+5)^5=1*(2x)^5+5*(2x)^4*5+10*(2x)^3*5^2+10*(2x)^2*5^3+5*(2x)*5^4+5^5

Third term is 10*8*x^3*25=2000 x^3

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