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OlgaM077 [116]
3 years ago
13

Need help please help

Mathematics
1 answer:
const2013 [10]3 years ago
3 0
Basically, when dealing with measurement problems such as these you ALWAYS need to have a key, or keys. The key(s) in this situation would be: 1 inch equals 12 feet, and 12 inches equals 1 foot. Now what you need to do is solve. So, width of the building's lot is 114 feet. You want to divide that by twelve because, remember one of the key(s) is 1 inch=12 feet. So the twelve you are dividing by is the 1 inch= 12 feet equation. Now when you divide 114÷12, you get the answer of 9.5, AKA 9 1/2. And now to check the answer, multiply 9.5 with 12, and that would give you 114. I hope this helps!
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Write the point where the linear equation 3x + 4y = 12 cuts the x-axis.​
Pani-rosa [81]

Answer:

When the eqn cuts the x-axis , y=0

3x=12

x=12/3

x=4

So,at x=4 is the point at which the linear equation cuts the x-axis

7 0
2 years ago
Read 2 more answers
HELP PLEASE
Fantom [35]

Answer:

Option C

Step-by-step explanation:

You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.

The total cost has to be in units of $.

There are two types of costs in the problem:

Those that depend on the number of days ($/day )

Those that depend on the number of students and the number of days ($/(student * day))

If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'

So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:

3 days (Cost of training + Cost of food Miscellaneous expenses :).

Therefore the correct answer is option C:

C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.

The expression that represents the total expense should have a formula similar to this:

y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars

y = 3 ($ 100b + $ 200) + $ 1050

3 0
3 years ago
Read 2 more answers
The graph shows the relationship.....
Anna35 [415]

Answer:

Part A: That 6 pounds of rice costs $18

Part B: (1,3) represents the unit price

Part C: 4 pounds of rice, because $12/3 equals 4

Step-by-step explanation:

Part A: The first point, 6, is on the amount of rice axis and the second point, 18, is on the total cost axis.

Part B: The unit price means the price for just 1 of something, so if you go to 1 pound of rice on the graph, you see it's at 3 on the total cost axis. Which means that 1 pound of rice costs $3.

Part C: From Part B you know that 1 pound of rice equals $3. So if you spend $12, then you can divide that by $3 to see how many pounds of rice you bought. 12/3 equals 4, so you bought 4 pounds of rice. Or you can count by 3's until you get to 12: 3, 6, 9, 12. That's 4 times so that means you bought 4 pounds of rice.

5 0
3 years ago
If you were asked to load 225 bixes on a truck , and boxes are crated. With each nine boxes how many crates would you need to lo
Lubov Fominskaja [6]
225 divided by 9 to figure out the number of crates needed.
225/9=25

So 25 crates are needed to load all boxes on the truck.
4 0
3 years ago
The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the
lana66690 [7]

Answer:

Width= 13 cm

length=30cm

Step-by-step explanation:

Let the length of the rectangle be 'L'

And the width of the rectangle be 'W'

Perimeter= 86 cm

According to the statement:

        Length= 2*Width+4\\L=2W+4

Perimeter of a rectangle= 2(Length+Width)

86=2(2W+4+W)\\86/2=3W+4\\43=3W+4\\3W=43-4\\3W=39\\W=39/3\\W=13 cm\\\\Length(L)=2W+4\\=2(13)+4=26+4=30 cm\\Length=30 cm

                               Width= 13 cm

                                length=30cm

6 0
3 years ago
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